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A particle starts from rest with a constant acceleration and its velocity after t second is v. The displacement of the particle in last two second of its motion is equal to

deeksha bansal , 6 Years ago
Grade 12th pass
anser 1 Answers
Sai venkat

Last Activity: 6 Years ago

V=u +at If v is the velocity 2 seconds before I.e at t=n-2Therefore v=0+a(n-2)=a(n-2)Now displacement s=ut+1/2 at ^2So displacement in last 2 seconds isS={a(n-2)}2+1/2 a (2)^2I.e s=2an-2a or a=2a(n-1)

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