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```
A particle starts from rest has an acceleration of a =2tm/s^2 then distance travelled in first second

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3 years ago

```							Initial velocity is zero And question asked is distance traveled in 1st secondS=u + a/2(2n-1)U =0a=2m/s^2n=1So put this in formula Answer would be 1m
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3 years ago
```							Given thata=2tnow we know that dv / dt = 2tdv = 2t dtintegrate itv = t2now we know that ds/ dt = vds  = t2 dtintegrate its = t3/3hence in first second put t = 1 secondhences = 1/3 metrehope it helps
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3 years ago
```							Acceleration, (a) = 2tv= 2t^2/2 + constant= t2@ t= 0 v= 0So could constant term is zero V= t2Now, X = t^3/3 +cAt t= 0, X= 0So X = T3/3So distance covered in 1 sec X=1/3
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3 years ago
```							Since acceleration of body is not constant we have to integrate it two times and the result will be x=1/3 metres, where x is displacement
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3 years ago
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