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Grade: 12th Pass

                        

A particle starting from rest moves in a straight line with acceleration as shown in the a-t graph.Find the distance(in m) traveled by the particle in the first four seconds from start of its motion.

5 years ago

Answers : (3)

Shubham Singh
199 Points
							
first make v-t graph then calculate area under that graph
5 years ago
Dal Chand sharma
13 Points
							
When t=0,then a=1
When a=1,then t=0 
When time=4,thena=4
Given u=0
S=ut+1/2at^2
S=1/2(4)(4)^2
Then,S=32
one year ago
Sanjay Singh
13 Points
							
Here we have to put this graph in the equation of straight line as Y,=MX+c.with negative slope.here we will get a(t)=1-t.now we integrate it to find velocity which will be v=t-t2/2(here t2 means t square).now again we will integrate it to get distance covered which will be s=t2/2-t3/6.now we will put t=1 ...2...3....and 4 to get distance covered and then we will add all of them to get total distance covered..answer would be 4.01m.
one year ago
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Course Features

  • 101 Video Lectures
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Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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