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Mechanics

a particle starting from rest and moving with an acceleration 4/3m/s-2 , what is the distance travelled by particle in third second?

shivani

12 Years agoGrade

4 Answers

Amit Nardiya

12 Years ago

Thanks & Regards,

Amit Nardiya,

askIITians faculty.

Shivam jangra

8 Years ago

u=0,aceeleration=4/3 and time(t)=3sec. The above all data is given in problemWe have to find out the distance travelled in 3rd second .We can find it out asDistance travelled in 3rd sec. -distance travelled in 2nd sec. And we will use the equationS=ut+1/2at^2S=(0)3+1/2(4/3)(3)^2-(0)2+1/2(4/3)(2)^2S=0+6-8/3S=(18-8)/3=10/3Hence the distance travelled in 3rd sec. Is 10/3m.

Nithish

7 Years ago

use the formula for displacement in nth second

Sn=u+a/2(2n-1)

here u=0 as it is starting from rest,a=4/3m/s^2

S3=0+4/6(2(3)-1)

S3=4/6(5)

S3=20/6

S3=10/3 m

Kushagra Madhukar

5 Years ago

Dear student,

Please find the solution to your problem.

Using the formula for displacement in nth second

S_n= u + a/2(2n-1)

here, u = 0 as it is starting from rest, a=4/3m/s²

S₃= 0 + 4/6(2(3) – 1)

S₃ = 4/6(5)

S₃ = 20/6

S₃ = 10/3 m

Thanks and regards,

Kushagra

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