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`        A particle start moving with a constant angular acceleration Alpha in a circular path .The time at which the magnitude of tangential and radial acceleration are equal is:`
one year ago

Arun
23506 Points
```							As we realize that Centripetal speeding up = v^2/r To start with condition of movement ω = ωo+ αt As beginning rakish speed is 0 ω = αt v/r = at v = atr. Extraneous increasing speed = centripetal quickening αr = a ar = v^2/r ar = (atr)2/r a =  a^2t^2 t = 1/sqrt (a)
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions