A particle start moving from rest state along a straight line under the action the action of a constant force and travel distance x in the first five seconds . The distance travelled by it in next five seconds will be.

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Hasan Naqvi · Answer

We know that, s= ut + 1/2 at 2 u=0, and a= constant x= ½ a * 5 * 5 = 12.5 a Distance traveled in 10s = ½ * a * 10 * 10 = 50 a= 4x So distance travelled between 5-10s = 3x

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A particle start moving from rest state along a straight line under the action the action of a constant force and travel distance x in the first five seconds . The distance travelled by it in next five seconds will be.

A particle start moving from rest state along a straight line under the action the action of a constant force and travel distance x in the first five seconds . The distance travelled by it in next five seconds will be.

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A particle start moving from rest state along a straight line under the action the action of a constant force and travel distance x in the first five seconds . The distance travelled by it in next five seconds will be.

A particle start moving from rest state along a straight line under the action the action of a constant force and travel distance x in the first five seconds . The distance travelled by it in next five seconds will be.

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