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```
A particle start moving from rest state along a straight line under the action the action of a constant force and travel distance x in the first five seconds . The distance travelled by it in next five seconds will be.

```
5 years ago

Hasan Naqvi
97 Points
```							We know that,s= ut + 1/2 at2u=0, and a= constant x= ½ a * 5 * 5 = 12.5 aDistance traveled in 10s = ½ * a * 10 * 10 = 50 a= 4x So distance travelled between 5-10s = 3x
```
5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions