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A particle P is projected from a point 0 with s velocity of 25m/s at an angle of 60 degrees above the horizontal How many seconds is P at least 15m above the level of 0

Dimeji bankole , 6 Years ago
Grade 12th pass
anser 1 Answers
Adarsh

Last Activity: 6 Years ago

Vertical velocity of particle = vSin(theta)
v= 25m/s
Sin(theta)=Sin60=root(3)/2
As we know V=distance/time
Distance given=15
Time=15x2/25xroot(3)
=2root(3)/5 sec
 
=>2

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