Grade 12th passMechanics

A particle originally at rest at the highest point of a smooth vertical circle is slightly displaced. It will leave the circle at a vertical distance h below the highest point such that
(a)h=R (b)h=R/3 (c)h=R/2 (d)h=2R/3
(R is the radius of the circle it is moving in)

Anant Kumar Thakur

7 Years agoGrade 12th pass

3 Answers

Arun

Approved Tutor Answer7 Years ago

Dear Anant

I am getting my answer as h = R/3

Please let me know is thisis correct then I will share my solution

Anant Kumar Thakur

7 Years ago

yeah thats the answer please share the solution...................................................................

Khimraj

7 Years ago

let angle made by particle with verticl line is $\Theta$

when centrifugal force (mv²/r) become greater than or equal tocomponent of mg along center (mgcos $\Theta$ )

mv²/R >= mgcos $\Theta$

m(2gh)/r = mg(R-h)/R

2h = R-h

so h = R/3

Hope it clears......................

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A particle originally at rest at the highest point of a smooth vertical circle is slightly displaced. It will leave the circle at a vertical distance h below the highest point such that(a)h=R (b)h=R/3 (c)h=R/2 (d)h=2R/3(R is the radius of the circle it is moving in)

Anant Kumar Thakur

3 Answers

Arun

Anant Kumar Thakur

Khimraj

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A particle originally at rest at the highest point of a smooth vertical circle is slightly displaced. It will leave the circle at a vertical distance h below the highest point such that
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