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A particle originally at rest at the highest point of a smooth vertical circle is slightly displaced. It will leave the circle at a vertical distance h below the highest point such that(a)h=R (b)h=R/3 (c)h=R/2 (d)h=2R/3(R is the radius of the circle it is moving in)

Anant Kumar Thakur , 6 Years ago
Grade 12th pass
anser 3 Answers
Arun

Last Activity: 6 Years ago

Dear Anant
 
I am getting my answer as h = R/3
 
Please let me know is thisis correct then I will share my solution

Anant Kumar Thakur

Last Activity: 6 Years ago

yeah thats the answer please share the solution...................................................................

Khimraj

Last Activity: 6 Years ago

let angle made by particle with verticl line is \Theta
when centrifugal force (mv2/r) become greater than or equal tocomponent of mg along center (mgcos\Theta)
mv2/R >= mgcos\Theta
m(2gh)/r = mg(R-h)/R
2h = R-h
so h = R/3
Hope it clears......................

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