Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass

A particle originally at rest at the highest point of a smooth vertical circle is slightly displaced. It will leave the circle at a vertical distance h below the highest point such that
(a)h=R (b)h=R/3 (c)h=R/2 (d)h=2R/3
(R is the radius of the circle it is moving in)
one year ago

## Answers : (3)

Arun
23359 Points

Dear Anant

I am getting my answer as h = R/3

Please let me know is thisis correct then I will share my solution
one year ago
Anant Kumar Thakur
23 Points

yeah thats the answer please share the solution...................................................................
one year ago
Khimraj
3008 Points

let angle made by particle with verticl line is $\Theta$
when centrifugal force (mv2/r) become greater than or equal tocomponent of mg along center (mgcos$\Theta$)
mv2/R >= mgcos$\Theta$
m(2gh)/r = mg(R-h)/R
2h = R-h
so h = R/3
Hope it clears......................
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details