Grade 10Mechanics

A particle of mass m starts from rest and moves in a circular path of radius r with uniform angular acceleration a. The kinetic energy of the particle after n revolutions is

unmukt

9 Years agoGrade 10

1 Answer

deepak

9 Years ago

by newtons eqn of motion, $\omega ^2 = 2\alpha s$

where $\omega$ is angular velocity

s is distance covered (s=n2 $\pi$ r)

and alpha is the angular acceleration( $\alpha$ =a)

hence

$\omega ^2 = 2a(4\pi n r)$

we know that

v $= \omega r$ (where v is the linear velocity)

hence v² = $\omega^2 r^2$

v²= $n8a \pi r^3$

since,

KE= ½ (m)v^2

=>K.E.=1/2×(m)× $n8a \pi r^3$

hope this is useful and p.s. dont do these kinds of problems involving rotational motion.

do it only after eleventh and take it slow and steady.

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A particle of mass m starts from rest and moves in a circular path of radius r with uniform angular acceleration a. The kinetic energy of the particle after n revolutions is

unmukt

1 Answer

deepak

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