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`        A particle of mass m moving in the x-direction with speed 2v is hit by another particle of mass 2m moving in the y-direction with speed v. If the collision is perfectly inelastic, the percentage loss in the energy during the collision is close to : `
2 years ago

763 Points
```							initial energy of system before collision = ½.m.4v2+ ½.2m.v2 =  3.m.v2in inelastic collision two particle will stick together and their momentum will be conserved .so,  4mv = 3m.v” => v” = 4/3v.so the velocity after collision is 4/3 times the velocity before collision.now, energy after collision = ½.3m.(4/3v)2= 8m/3.v2%loss in kinetic energy = 100 – 3.m.v2/8/3.m.v2 x 100 = 11.11% Thanks and Regards Adarsh
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions