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Grade 11Mechanics

A particle of mass M is projected with speed v m/s at an angle 30° with horizontal from ground . Its K.E at the topmost point of the trajectory is?

Profile image of Tanisha
8 Years agoGrade 11
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1 Answer

Profile image of Yashwant yadav
8 Years ago
Breaking components in projectile....vcos30 for horizontal which is still be there at the topmost point,Now k.e is 1/2mv² where v is vcos 30 ,so by calculating 1/2m *(v√3/2)²= 3/8mv² answer: