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Grade 11Mechanics

a particle of mass m is projected from originat an angle theta with positive x axis find angular momentum of particle at any time t about o

Profile image of Abhi
9 Years agoGrade 11
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1 Answer

Profile image of Vikas TU
9 Years ago
I have already answered this qstn.
Since U have asked this twice,
Angular momentum is mvr where r is the perpendicular distance to momenta.
In x – direcn. at any time t,
Vx = ucos(thetha).....................................(1)
x = ucos(thetha)*t.............................(2)
In y – direc. at any time t,
Vy  =  usin(thetha) – gt...............................(3)
y = usin(thetha) – 0.5gt^2......................(4)
from eqn. (2) and (4) we have got the coordinates.
Now distance b/w origin to the those coordinates =>
that is r = > root( (usin(thetha) – 0.5gt^2)^2  +   (ucos(thetha)*t)^2)
and v = root(Vx^2 + Vy^2)
Hence the final angular momentum at time t => mvr
that is=>    m * root(Vx^2 + Vy^2) *  root( (usin(thetha) – 0.5gt^2)^2  +   (ucos(thetha)*t)^2)
or
=> m * root((ucos(thetha))^2 +  (usin(thetha) – gt)^2) *  root( (usin(thetha) – 0.5gt^2)^2  +   (ucos(thetha)*t)^2)