a particle of mass m is projected from origin with speed u at an angle theta with positive x asis find angular momentum of particle at any time t about origin

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Vikas TU · Answer

Angular momentum is mvr where r is the perpendicular distance to momenta. In x – direcn. at any time t, Vx = ucos(thetha).....................................(1) x = ucos(thetha)*t.............................(2) In y – direc. at any time t, Vy = usin(thetha) – gt...............................(3) y = usin(thetha) – 0.5gt^2......................(4) from eqn. (2) and (4) we have got the coordinates. Now distance b/w origin to the those coordinates => that is r = > root( (usin(thetha) – 0.5gt^2)^2 + (ucos(thetha)*t)^2) and v = root(Vx^2 + Vy^2) Hence the final angular momentum at time t => mvr that is=> m * root(Vx^2 + Vy^2) * root( (usin(thetha) – 0.5gt^2)^2 + (ucos(thetha)*t)^2) or => m * root((ucos(thetha))^2 + (usin(thetha) – gt)^2) * root( (usin(thetha) – 0.5gt^2)^2 + (ucos(thetha)*t)^2)

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a particle of mass m is projected from origin with speed u at an angle theta with positive x asis find angular momentum of particle at any time t about origin

a particle of mass m is projected from origin with speed u at an angle theta with positive x asis find angular momentum of particle at any time t about origin

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