Grade 11Mechanics

a particle of mass m is projected from origin with speed u at an angle theta with positive x asis find angular momentum of particle at any time t about origin

Abhi

9 Years agoGrade 11

1 Answer

Vikas TU

9 Years ago

Angular momentum is mvr where r is the perpendicular distance to momenta.

In x – direcn. at any time t,

Vx = ucos(thetha).....................................(1)

x = ucos(thetha)*t.............................(2)

In y – direc. at any time t,

Vy = usin(thetha) – gt...............................(3)

y = usin(thetha) – 0.5gt^2......................(4)

from eqn. (2) and (4) we have got the coordinates.

Now distance b/w origin to the those coordinates =>

that is r = > root( (usin(thetha) – 0.5gt^2)^2 + (ucos(thetha)*t)^2)

and v = root(Vx^2 + Vy^2)

Hence the final angular momentum at time t => mvr

that is=> m * root(Vx^2 + Vy^2) * root( (usin(thetha) – 0.5gt^2)^2 + (ucos(thetha)*t)^2)

=> m * root((ucos(thetha))^2 + (usin(thetha) – gt)^2) * root( (usin(thetha) – 0.5gt^2)^2 + (ucos(thetha)*t)^2)

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a particle of mass m is projected from origin with speed u at an angle theta with positive x asis find angular momentum of particle at any time t about origin

Abhi

1 Answer

Vikas TU

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