A particle of mass M is projected at time t=0 from a point P on the ground with speed v at an angle 60 degrees to the horizontal, the angular momentum of the particle at t=v/g about point of projection will be: My approach was to calculate horizontal range corresponding to time v/g. Multiplying that with mg gives me torque. Now torque is rate of change of angular momentum. And this way I calculated angular momentum but my answer didn`t match. However I didn`t find anything wrong in my concept. Can some one tell me where I am wrong? Thanks in advance.

Three identical balls are placed on a frictionless horizontal surface touching each other. They stick to each other because of adhesive. Another ball of same radius and mass m is placed over the void created by the three balls. Find the forces applied by the balls kept on the floor to each other if the system remains in equilibrium.

A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.

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