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Grade 11Mechanics

a particle of mass M is moved rectilinearly under constant power P. At some instant after the start, its speed is v and at a later instant, the speed is 2v. Neglecting friction, distance travelled in m by the particle as its speed increases from v to 2v is 7x. Find x(take P=4watt, M=12kg , v= 3m/s)

Profile image of Abhishek Anand
8 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

To solve this problem, we need to analyze the motion of a particle under constant power. The key here is to understand how power relates to force, speed, and distance. Let's break it down step by step.

Understanding Power and Motion

Power (P) is defined as the rate at which work is done or energy is transferred. In the context of a particle moving under constant power, we can express power in terms of force (F) and velocity (v) as follows:

P = F * v

From this equation, we can derive the force acting on the particle:

F = P / v

Acceleration and Force Relationship

According to Newton's second law, the force acting on an object is also equal to the mass (M) of the object multiplied by its acceleration (a):

F = M * a

By equating the two expressions for force, we have:

M * a = P / v

From this, we can express acceleration as:

a = P / (M * v)

Finding Distance Traveled

We need to find the distance traveled by the particle as its speed increases from v to 2v. To do this, we can use the relationship between acceleration, velocity, and distance. We know that:

a = dv/dt

We can also express acceleration in terms of velocity:

a = (dv/dt) = (dv/dx) * v

Substituting our expression for acceleration into this equation gives us:

dv/dx = P / (M * v^2)

Integrating to Find Distance

To find the distance traveled as the speed increases from v to 2v, we can integrate:

dx = (M * v^2 / P) dv

Now, we integrate from v to 2v:

x = (M / P) * ∫(v^2) dv

Calculating the integral:

x = (M / P) * [v^3 / 3] from v to 2v

Substituting the limits:

x = (M / P) * [(2v)^3 / 3 - (v)^3 / 3]

This simplifies to:

x = (M / P) * [(8v^3 - v^3) / 3]

x = (M / P) * (7v^3 / 3)

Plugging in the Values

Now, we can substitute the given values into our equation:

  • P = 4 W
  • M = 12 kg
  • v = 3 m/s

Substituting these values into the equation for x:

x = (12 kg / 4 W) * (7 * (3 m/s)^3 / 3)

Calculating this step-by-step:

x = 3 kg/W * (7 * 27 m^3/s^3 / 3)

x = 3 kg/W * (63 m^3/s^3)

x = 189 kg*m^2/(W*s^3)

Since 1 W = 1 kg*m^2/s^3, we can simplify:

x = 189 m

Final Result

Thus, the distance traveled by the particle as its speed increases from v to 2v is:

7x = 7 * 189 m = 1323 m

So, the value of x is 189 m. This means that as the particle accelerates from 3 m/s to 6 m/s, it travels a distance of 1323 meters. This example illustrates the relationship between power, mass, and motion in a clear and practical way.