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```
a particle of mass m is acted upon by a force F=F o cos{(pie/2)t}. the distance travelledby the particle when it stops first[initial velocity of the particle is zero) is .Is the answer 8f/m pi^2

```
8 months ago

Arun
25768 Points
```							P=FVP=mavP=mv . dv/ds . vP/m.ds =v^2.dvIntegrate both sides under limitsV from v1 to v2ds from 0 to SWe get(v^3/3)v1tov2=P/m.s1/3(v2^3-v1^3)=P/m.SM/3P(v2^3-v1^3)=S
```
8 months ago
Vikas TU
14146 Points
```							Dear student v = 2* f1 / (pi * m)integrate with limits 0 to 1as f=0 when t = 1Good Luck …...........
```
8 months ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions