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Grade 12Mechanics

A particle of mass M in circular motion on rough surface at an instant has velocity `v` and increases at rate `a`. What is the minimum value of MU or U . Got it for HC Verma. Answer is `a/g`

Profile image of vrun
12 Years agoGrade 12
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1 Answer

Profile image of shwetank
12 Years ago
Here the circular motion on rough surface is possible because of the force of friction, therefore
(U)Mg = Mv^2/r    (r = radius of circle)
(U) = v^2/rg
But v^2/r = a
So,
(U) = a/g