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        a particle of mass 3m is projected from ground with velocity 20 root 2 at 45 degrees at highest point it explodes into two pieces. one of mass 2m and other of mass m.both moves in opposite direction horizontally.mass 2m falls at a distance of 100m from point of projection. the distance of second mass from point of projection is...
3 years ago

## Answers : (2)

Nishant Vora
IIT Patna
2467 Points
							soln

3 years ago
Manas Shukla
102 Points
							In this problem the easiest way to solve is you can assume that the centre of mass of the particle will continue to follow projectile motion.As we know particle of mass 2m lands at 100m.Time periodv = u + at$20\sqrt{2} \sin 45 =10t$ taking g = 10m/s2t = 2 sec = half of flight so total time = 4 secSo range of projectile if it had not exploded = 80mSo the com of the particle will also land at 80 mthus$80 = \frac{2m\times 100 + x}{3m}$x = 40m.

3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions