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A particle of mass 2 kg starts from rest on a inclined smooth surface with inclination 30 degree and length 2 metre after travelling along incline it is made to move on frictional horizontal surface the maximum distance it will travel before coming to rest on a frictional surface with frictional coefficient of 0.25 is
A particle of mass 2 kg starts from rest on a inclined smooth surface with inclination 30 degree and length 2 metre after travelling along incline it is made to move on frictional horizontal surface the maximum distance it will travel before coming to rest on a frictional surface with frictional coefficient of 0.25 is

```
4 years ago

Vikas TU
14146 Points
```							After travelling 2 mter distance, final velocity becomes as,v^2 = 0^2 + 2gsin30*2v = root(20) = m/s. From friction sufrace starts, we would appyly WET,Hence,-(0.25*2*g*cos30)*x  = 0 –  0.5*2*v^2  { friction force is negative}put v value and solve we get,x = 2.312 meter.
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions