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A particle of mass 2 kg moves with initial velocity of v=4i+4j. a constant force of F=-20j N is applied on the particle. initially particle was at (0,0) . the X-coordinate of the particle when it's y coordinate again becomes zero is given by
Let the particle travel for time t, then coordinate of position after time t will be(x, 0). Now F=ma; -20=2•a j; a=-10jm/s2as there is no displacement along y direction hence s=0 we use newtons second law of motion. S=ut+0.5at2.0=4t--0.5•10t24t=5t2t=0.8s Now displacement along i is x i and velocity is 4i.Then 4=x/t ; x=3.2 Hence coordinate is (3.2, 0).
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