A particle of mass 2 kg is subjected to a two dimensional Conservative force given by F x = (-2x+2y) , F y = (2x-y²) (x, y in m and F in N). If particle has kinetic energy of 8/3 J at point (2,3), find speed (in m/s) of the particle when it reaches (1,2)

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Raj150 · Answer

given F=(-2x+2y)i ^ +(2x-y 2 )j ^ KE i =8/3J let S=(d x )i ^ +(d y )j ^ Work Done=Change in K.E F.S=(1/2)m(v 2 -u 2 ) ∫[(-2x+2y)i ^ +(2x-y 2 )j ^ ][(d x )i ^ +(d y )j ^ ]=v 2 -64/9 ∫(-2x+2y)d x +(2x-y 2 )d y =v 2 -64/9 2 ∫ 1 -2xd x + 3 ∫ 2 -y 2 d y +∫2yd x +∫2xd y =v 2 -64/9 3+19/8+ (2,3 ) ∫ ( 1,2 ) d(2xy)=v 2 -64/9 28/3+4-12=v 2 -64/9 After Solving The Above Equation We Get V=2.905m/s

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A particle of mass 2 kg is subjected to a two dimensional Conservative force given by F x = (-2x+2y) , F y = (2x-y²) (x, y in m and F in N). If particle has kinetic energy of 8/3 J at point (2,3), find speed (in m/s) of the particle when it reaches (1,2)

A particle of mass 2 kg is subjected to a two dimensional Conservative force given by F_x= (-2x+2y) , F_y = (2x-y²) (x, y in m and F in N). If particle has kinetic energy of 8/3 J at point (2,3),
find speed (in m/s) of the particle when it reaches (1,2)

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A particle of mass 2 kg is subjected to a two dimensional Conservative force given by F x = (-2x+2y) , F y = (2x-y²) (x, y in m and F in N). If particle has kinetic energy of 8/3 J at point (2,3), find speed (in m/s) of the particle when it reaches (1,2)

A particle of mass 2 kg is subjected to a two dimensional Conservative force given by Fx= (-2x+2y) , Fy = (2x-y²) (x, y in m and F in N). If particle has kinetic energy of 8/3 J at point (2,3),find speed (in m/s) of the particle when it reaches (1,2)

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A particle of mass 2 kg is subjected to a two dimensional Conservative force given by F_x= (-2x+2y) , F_y = (2x-y²) (x, y in m and F in N). If particle has kinetic energy of 8/3 J at point (2,3),
find speed (in m/s) of the particle when it reaches (1,2)