Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A particle of mass 2 kg is subjected to a two dimensional Conservative force given by F x = (-2x+2y) , F y = (2x-y²) (x, y in m and F in N). If particle has kinetic energy of 8/3 J at point (2,3), find speed (in m/s) of the particle when it reaches (1,2)

A particle of mass 2 kg is subjected to a two dimensional Conservative force given by Fx= (-2x+2y) , Fy = (2x-y²) (x, y in m and F in N). If particle has kinetic energy of 8/3 J at point (2,3),
find speed (in m/s) of the particle when it reaches (1,2)

Grade:11

1 Answers

Raj150
13 Points
one year ago
given F=(-2x+2y)i^+(2x-y2)j^
         KEi=8/3J
let S=(dx)i^+(dy)j^ 
   Work Done=Change in K.E
              F.S=(1/2)m(v2-u2)
  •           ∫[(-2x+2y)i^+(2x-y2)j^][(dx)i^+(dy)j^]=v2-64/9
  •          ∫(-2x+2y)dx+(2x-y2)dy=v2-64/9
  •         21-2xdx+32-y2dy+∫2ydx+∫2xdy=v2-64/9
  •         3+19/8+(2,3)(1,2)d(2xy)=v2-64/9
  •         28/3+4-12=v2-64/9
        After Solving The Above Equation We Get
                              V=2.905m/s
      

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free