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        A particle of mass 2 kg is moving such that at time t, its position, in meter, is given by r(t) = 5i + 2t2j. The angular momentum of the particle at t = 2s about the origin in kg m-2s-1 is :a) -80 kb) (10i - 16j)c) - 40 kd) 40 k
one year ago

Khimraj
3008 Points
							velocity v = dr/dt = -4t$\hat{j}$angular momentum = rXmv= (5$\hat{i}$ -2t2$\hat{j}$)Xm(-4t$\hat{j}$)= -20mv$\hat{k}$= -20*2*2$\hat{k}$= -80$\hat{k}$Hope it clears....................................

one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions