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Grade: 11
        
A particle of mass 2 kg is moving such that at time t, its position, in meter, is given by r(t) = 5i + 2t2j. The angular momentum of the particle at t = 2s about the origin in kg m-2s-1 is :
a) -80 k
b) (10i - 16j)
c) - 40 k
d) 40 k
one year ago

Answers : (1)

Khimraj
3008 Points
							
velocity 
v = dr/dt = -4t\hat{j}
angular momentum = rXmv
= (5\hat{i} -2t2\hat{j})Xm(-4t\hat{j})
= -20mv\hat{k}
= -20*2*2\hat{k}
= -80\hat{k}
Hope it clears....................................
one year ago
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