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Grade: 11
        A particle of mass 0.1 Kg is executing simple harmonic motion of amplitude 1 m and time period 0.2 SEcond -The maximum force on the particle will be (1)9 N (2)99 N (3) 9.9 N (4) 0.99 N
3 years ago

Answers : (1)

DIVYA SINGH
13 Points
							
HERE,
START AT ORIGIN AND VELOCITY IS OF NO USE, ONLY THING NEEDED IS THE AREA UNDER GRAPH
 
K.E = AREA OF F-S GRAPH
½ MV= ½ ×4 ×10 + 4 × 10 + ½× 4 ×10
M=0.1
V2=1600
V=40M/S
 
one year ago
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