A particle moving with constant speed turns left by an

Question

A particle moving with constant speed turns left by an angle of 74° after travelling every 1 m distance. If it returns back to its staring pt. after 18 sec , then the magnitude of average acceleration of the particle frm its initial posn to just bfore it takes its 2nd turn is 10 k m/s² . Find k.

Ashutosh · Accepted Answer

Let number of turns be m, so 74°×m=360°×n i.e a multiple of 360°.So, m = 180Therefore speed = 180×1/18=10m/sNow average acceleration,a = (v1-v2)/(t1-t2) = V/TV = 10 - 10(cos 74° i + sin 74° j)So, magnitude of V = 12Now time taken for two turns = (18/180) ×2 = 1/5 secondsSo, a = V/T = 12/(1/5) = 60 m/s²So, k = 6

Electric Current> A particle moving with constant speed tur...

A particle moving with constant speed turns left by an angle of 74° after travelling every 1 m distance. If it returns back to its staring pt. after 18 sec , then the magnitude of average acceleration of the particle frm its initial posn to just bfore it takes its 2nd turn is 10 k m/s² . Find k.

Hrishant Goswami , 11 Years ago

Ashutosh

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Electric Current> A particle moving with constant speed tur...

A particle moving with constant speed turns left by an angle of 74° after travelling every 1 m distance. If it returns back to its staring pt. after 18 sec , then the magnitude of average acceleration of the particle frm its initial posn to just bfore it takes its 2nd turn is 10 k m/s2 . Find k.

Hrishant Goswami , 11 Years ago

Ashutosh

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