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A particle moving with a uniform acceleration travels 24m and 64m in the first two consecutive intervals of 4 seconds each. Its initial velocity is?
Dear Fatima s = ut + 1/2 at2so distance travelled in first 4 seconds = 24 = u(4) + 1/2 a(42) =>24 = 4u + 8a - (i)now total distance travelled in 8s = (24+64) = u(8) + 1/2 a(82) =>88 = 8u + 32a -(ii)multiplying equation (i) by 4 we have,96 = 16u + 32a-(iii)subtracting equation (ii) from equation (iii) we have,8 = 8u=> u = 1m/s RegardsArun
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