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Grade 12Mechanics

A particle moving on x axis has potential energy u=4-40x+10x*2 j along x axis. The particle is relaesed at x =-2m. The maximum value of x will be

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Profile image of Kavitha
8 Years agoGrade 12
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Profile image of SANJAY SHEKHAWAT
8 Years ago
first find -du/dx = 40-20x =force   then do -f.dx=du and integrate both side from x=-2 to x=x and u=124 to u=0 . ok