A particle moving on the x axis with a constant acceleration has displacement of 6m from t=4s to t=7s and 3m from t=5s to t=8s .Find the distance covered from t= 6 to t= 7s?

In this scenario, we have a particle moving on the x-axis with a constant acceleration. We are given two displacements: 6m from t=4s to t=7s and 3m from t=5s to t=8s. We need to find the distance covered from t=6s to t=7s.

Calculating the Total Displacement

To find the total displacement of the particle, we can add the two given displacements together. So, 6m + 3m = 9m.

Calculating the Total Distance Covered

The total distance covered is the sum of all the individual displacements. However, we need to consider that the particle might have moved back and forth during the given time intervals.

Since the particle is moving with a constant acceleration, we can use the formula:

Distance = Initial Velocity * Time + 0.5 * Acceleration * Time^2

Applying the Formula

From t=4s to t=7s, the displacement is 6m. So, from this information, we can calculate the initial velocity and acceleration for this time interval.

Similarly, from t=5s to t=8s, the displacement is 3m. We can calculate the initial velocity and acceleration for this time interval as well.

Once we have the initial velocity and acceleration for these intervals, we can calculate the distance covered from t=6s to t=7s using the same formula.

By following these steps, we can accurately determine the distance covered by the particle during the specific time interval you mentioned.