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`        A particle moving on the x axis with a constant acceleration has displacement of 6m from t=4s to t=7s and 3m from t=5s to t=8s .Find the distance covered from t= 6 to t= 7s? `
4 months ago

Saurabh Koranglekar
3154 Points
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4 months ago
Khimraj
3008 Points
```							s = ut + 1/2 at²6 = u(7-4) + 1/2a(7² - 4²) 6 = 3u + 33/2aSimilarly 3 = 3u + 39/2a by solving equations we get u  = 7.5 m/s and a = -1 m/s²we know s = ut + 1/2at² s = 7.5 x (9-6) + 1/2(-1) (9² - 6²) s = 22.5 - 22.5 = 0 m
```
4 months ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions