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`        a particle moves with a velocity v(t)=(1/2)kt^2 along a straight line,where is a positive constant. Find the average speed of particle in time t  `
6 months ago

Vikas TU
10049 Points
```							V = ½ Kt^2S is given by integral V . dt Put value of v nd solve S = Kt^3/6Average velocity s given by Distance travelled / T=> Kt^2/6
```
6 months ago
Arun
23513 Points
```							Velocity = kt^2 /2 distance travelled = Integration of v w.r.t = k t^3 /6 hence average speed = k t^3 /6 / t = k t^2 /6
```
6 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions