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        ​A particle moves with a deceleration √vInitial velocity is Vo. Find the time after which itwill stop
one month ago

Vikas TU
9762 Points
							Dear student v = u -at u = vo = initial velocity Acceleration = √vTime taken by particle to stop = t t = (v-v0)/a = -vo/√vGood Luck

one month ago
MAHESH KUMAR
13 Points
							a= -v½$\frac{dv}{v^{1/2}}= -dt$$\int_{v\circ }^{0}\frac{dv}{v^{1/2}}=-\int_{0}^{t}dt$$[\frac{v^{1/2}}{1/2}] v\circ \rightarrow 0 = -[t - 0]$      the integration is from $v\circ$ to zero $-\frac{v\circ ^{1/2}}{1/2}=-t$$t=2v\circ ^{1/2}$  This is the answer.All I have done is formed an equation as given in the question, variables being a and v.Then, I wrote a in terms of dv/dt and did further calculations to get t when velocity becomes zero

one month ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions