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Grade: 12
        A particle moves on a rough horizontal ground with some initial velocity say Vo. If (3/4)th of its kinetic energy is lost in time t0, then coefficient of friction between the particle and the ground is ?
4 years ago

Answers : (2)

Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
							Loss in KE = |work done by friction|
equate both x to get

Arun Kumar
IIT Delhi
Askiitians Faculty
4 years ago
Parul
11 Points
							3/4 energy is lost means 1/4 energy is left.So velocity becomes v•/2Now, v•/2=v• -ug×t•So u= v•/ 2gt•
						
11 months ago
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