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Grade 11Mechanics

A particle moves ina a straight line asX=4a[t+a sin(t/a)] x=position t in sec a is constant Q. THE VELOCITY IS 0 AT???? Please send fast I really need it now

Profile image of Debaraj Roy
9 Years agoGrade 11
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1 Answer

Profile image of Vikas TU
9 Years ago
X=4a [t+a sin (t/a)] 
(dx/dt) = 4a+ ( 4a2cos(t/an))/a 
(dx/dt) = 4a + 4acos (t/a) 
0 = 4a + 4a cos (t/a) 
- 4a = 4a cos (t/a) 
- 1 = cos (t/a) 
Cos π = cos (t/a) 
At t = a π , speed ends up noticeably zero