A particle moves in the xy plane and at time T at the point whose coordinates are (t^2,t^3-2t). Then at what instant of time will its velocity and acceleration vectors will be perpendicular to each other?
harsh jain , 6 Years ago
Grade 11
1 Answers
Khimraj
Last Activity: 6 Years ago
x = t2 + (t3 -2t)
v = dx/dt = 2t + (3t2 -2)
a = dv/dt = 2 + 6t
if v and a are perpendicular then v.a = 0
4t + 18t3 – 12t = 0
2t(9t2 – 4) = 0
so t = 2/3 sec
Hope it clears. If you like answer then please approve my answer.
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