A particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement x is proportional toa) xb) exc) x2d) logex
satendra , 10 Years ago
Grade 12th pass
3 Answers
Vasantha Kumari
Last Activity: 10 Years ago
Pranit
Last Activity: 5 Years ago
Loss of KE=1/2mv^2-1/2mu^2
=1/2m(v^2-u^2)
a=dv/dt ,so
- dv/dt=Kx
=-vdv/dc=Kx
On integrating both sides we get
{On the limits u and
Vdv=-k({on the limits x and 0)=kxdx
=V^2-u^2/2=- kx^2/2
Since there was no option for choosing integratiom symbol have used { (as an alternative)
Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
Please find the attached answer to your problem below.
Hope it helps.
Thanks and regards,
Kushagra
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free