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Grade: 12th pass

                        

A particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement x is proportional to a) x b) e x c) x 2 d) log e x

6 years ago

Answers : (3)

Vasantha Kumari
askIITians Faculty
38 Points
							
181-1898_retardation.jpg
6 years ago
Pranit
13 Points
							
Loss of KE=1/2mv^2-1/2mu^2
=1/2m(v^2-u^2)
a=dv/dt ,so 
- dv/dt=Kx
=-vdv/dc=Kx
On integrating both sides we get
{On the limits u and
Vdv=-k({on the limits x and 0)=kxdx
=V^2-u^2/2=- kx^2/2
Since there was no option for choosing integratiom symbol have used {  (as an alternative)
 
 
one year ago
Kushagra Madhukar
askIITians Faculty
605 Points
							
Dear student,
Please find the attached answer to your problem below.
 
 
Hope it helps.
Thanks and regards,
Kushagra
4 months ago
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