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Grade: 11
        A particle moves in a straight line with a velocity |t-4| where t is time in seconds the distance covered by the particle in 8 s is
2 years ago

Answers : (1)

Sanju
106 Points
							
Since Im unable to upload the v vs t i will explain how the graph looks like. Velocity is taken on y-axix and time on x-axis. The graph will look like the letter M. It will form 2 right angled triangle. Triangle AOB & BCD. Here O is the origin and A is the point on y axis [positive axis]. OA = 4 m.. OB =4m..Coming to triangle BCD, CD is parallel to OA and is located at  a distance of 8 units from origin O in the x-axis..CD=4m and BD= 4m...
 
Distance covered by the particle in 8 sec = area of triangle AOB + area of triangle BCD = 8+8 = 16 m
2 years ago
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