A PARTICLE MOVES IN A STRAIGHT LINE AND ITS POSITION X AT TIME T IS GIVEN BY X 2 =2+T ITS ACC. GIVEN

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Antara · Answer

x^2=2+T Differentiating both sides, 2xdx=dT So, v= dx/dT=1/2x acceleration(a)=dv/dT=(dv/dx)*(dx/dT) ….(Chain rule)

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A PARTICLE MOVES IN A STRAIGHT LINE AND ITS POSITION X AT TIME T IS GIVEN BY X 2 =2+T ITS ACC. GIVEN

A PARTICLE MOVES IN A STRAIGHT LINE AND ITS POSITION X AT TIME T IS GIVEN BY X² =2+T ITS ACC. GIVEN

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A PARTICLE MOVES IN A STRAIGHT LINE AND ITS POSITION X AT TIME T IS GIVEN BY X 2 =2+T ITS ACC. GIVEN

A PARTICLE MOVES IN A STRAIGHT LINE AND ITS POSITION X AT TIME T IS GIVEN BY X2 =2+T ITS ACC. GIVEN

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A PARTICLE MOVES IN A STRAIGHT LINE AND ITS POSITION X AT TIME T IS GIVEN BY X² =2+T ITS ACC. GIVEN