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A particle moves in a straight line and its position x at the time t is given by x^=2+t its acceleration is given by
X^2 = 2 + td(x^2) / dv = d(2 + t)/dv2dx/dv = dt/dv2xdx = dtdx/dt = 1/(2x)v = 1/(2x)Differentiating above equationdv/dx = -1/(2x^2)Acceleration is given bya = vdv/dx= 1/(2x) * -1/(2x^2)= -1/(4x^3)It’s acceleration is given by -1/(4x^3)
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