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`        a particle moves along x axis with acceleration a = a(0)[1-t/T] where a(0) and T are constantsif velocity at t=0 is zero then find the average velocity from t=0 to the time when a=0`
4 years ago

Nicho priyatham
625 Points
```							time wn a=0 is t=Tso u need to find  vavg in intevral t=0 to t=Tso vavg=(dist covered)/Tnow find distance coveredon integration v=∫a(t)dt     v=∫a(0)(1-(t/T))dt  (take limits from 0 to v on LHS and o to t on RHS)       =a(0)(t-(t)2/2T)        s=∫vdt                           =∫a(0)(t-(t)2/2T)dt           =a(0)(t2/2-t3/6T)       (take limits from 0 to s on LHS and o to T on RHS)        =a(0)(T2/2-T3/6T)           =a(0)T2/3so now vavg= s/T                     =a(0)T/3 PLZ APPROVE  IF USEFUL and in case of further doubts ask in ans box
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions