×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A particle moves along x-axis under the action of a position dependent force f =(5x^2- 2X)N . work done by force on the particle when it moves from origin to X =3 is ?
A particle moves along x-axis under the action of a position dependent force f =(5x^2- 2X)N . work done by force on the particle when it moves from origin to X =3 is ?


2 years ago

Susmita
425 Points
							Work donedW=fdx=(5x2-2x)dxFor W ,integrate both side.The limit of x is 0 to 3.$W= \int_{0}^{3} (5x^2 -2x)dx$    $W=5[\frac{x^3}{3}]{_{0}^{3}}-2[\frac{x^2}{2}]{_{0}^{3}}$     $W=5[\frac{27}{3}]-2[\frac{9}{2}]$W=45-9=36NmHope this helps

2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

Post Question