A particle moves along the curve x2/9 + y2/4 = 1With constant speed v . Express its velocity vectorially as a function of (x,y).

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Grade 11Mechanics

A particle moves along the curve x²/9 + y²/4 = 1
With constant speed v . Express its velocity vectorially as a function of (x,y).

Purva Agrawal

7 Years agoGrade 11

1 Answer

Arun

Approved Tutor Answer7 Years ago

So, effectively, the displacement of the particle with respect to the reference co-ordinate axes is:-

s= (x^2)/9 + (y^2)/4 =1.

Now, velocity is ds/dt.

So, we partially differentiate the equation, first with respect to X, treating you as a constant. This gives the velocity of the particle. (Vx) in X direction.

Vx= (2/9)x (i)^

Similarly, to get Vy, partially differentiate with respect to y.

Vy= y/2 (j)^

So, the velocity vector is

V= (2/9)X (i)^ + y/2 (j)^.

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A particle moves along the curve x2/9 + y2/4 = 1With constant speed v . Express its velocity vectorially as a function of (x,y).

Purva Agrawal

1 Answer

Arun

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A particle moves along the curve x²/9 + y²/4 = 1
With constant speed v . Express its velocity vectorially as a function of (x,y).

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