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A particle moves along the curve x 2 /9 + y 2 /4 = 1 With constant speed v . Express its velocity vectorially as a function of (x,y).
A particle moves along the curve x2/9 + y2/4 = 1With constant speed v . Express its velocity vectorially as a function of (x,y).

```
2 years ago

Arun
25768 Points
```							So, effectively, the displacement of the particle with respect to the reference co-ordinate axes is:-s= (x^2)/9 + (y^2)/4 =1.Now, velocity is ds/dt.So, we partially differentiate the equation, first with respect to X, treating you as a constant. This gives the velocity of the particle. (Vx) in X direction.Vx= (2/9)x (i)^Similarly, to get Vy, partially differentiate with respect to y.Vy= y/2 (j)^So, the velocity vector isV= (2/9)X (i)^ + y/2 (j)^.
```
2 years ago
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• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions