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A PARTICLE MOVES ALONG A STRAIGHT LINE WITH UNIFORM ACCELERATION. IF P1 AND P2 ARE LINEAR MOMENTA WHILE CROSSING THE POINTS A AND B, WHAT IS MOMENTAUM WHILE CROSSING C WHICH IS THE MID POINT OF A AND ?????..... can u give me proof sir

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3 years ago

```							Uniform acceleration, let say the acceleration be a, and a will be constant.Now dv/dt =a assume he mass of object m and at point A assume the velocity be v1 and at the point B to velcity be v2Now distance between A and B can be calculated by v2=u2+2asso v22 =v12 + 2aS so the distance between A and B will be S=(v22 – v12)/(2a)at the midpoint, the distance will be S/2 so C is s/2 far from Aso velocity at Cvc2 =v12 + 2aS = v12  + 2a{(v22 – v12)/(2a)}(/2)=v12 +(v22 – v12)/2=(v22 + v12)/2So vc2 = (v22 + v12)/2 multiple by m2 both sidem2 vc2 = m2 (v22 + v12)/2Pc2 = (PA2 +PB2)/2
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3 years ago
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