Vikas TU
Last Activity: 6 Years ago
Acceleration is the double differentiation of displacement with respect to time.
.i.e. a = d2x/dt2
Therefore, dx/dt = 2√at + 2b = v (velocity)
Comparing from this the acceleration is : 2√a
Substituting the value of t from velocity in displacement x we get,
x = √a((v – 2b)/2√a)^2 + 2b(v – 2b)/2√a + c
x = (v – 2b)/(2*2√a) + 2b(v – 2b)/2√a + c
or
x = ((v – 2b)/2+ 2b(v – 2b))/2√a
Here 2√a is the acceleration and is inversely proportional to the x.
Hence, (A) option is correct.
