Grade 11Mechanics

A particle located in a 1 dimensional potential field has potential energy function U (x)= (a/x^4) - (b/x^2), where a and b are positive constants. The position of equilibrium x- corresponds to?

Arin Som

9 Years agoGrade 11

1 Answer

piyush gera

9 Years ago

simply we know that -du/dx=F. simply differentiate this expreesion by putting f=0(in equlibrium no force acte net force is 0) and get answer.(u= potential energy)

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A particle located in a 1 dimensional potential field has potential energy function U (x)= (a/x^4) - (b/x^2), where a and b are positive constants. The position of equilibrium x- corresponds to?

Arin Som

1 Answer

piyush gera

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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.11213141

If a=x² find the displacement at t =3sec if body velocity at t= 0 sec is 0

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