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A particle located in a 1 dimensional potential field has potential energy function U (x)= (a/x^4) - (b/x^2), where a and b are positive constants. The position of equilibrium x- corresponds to?
A particle located in a 1 dimensional potential field has potential energy function U (x)= (a/x^4) - (b/x^2), where a and b are positive constants. The position of equilibrium x- corresponds to?

```
4 years ago

piyush gera
23 Points
```							simply we know that -du/dx=F. simply differentiate this expreesion by putting f=0(in equlibrium no force acte net force is 0) and get answer.(u= potential energy)
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions