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Grade 12th passMechanics

A particle is thrown with an initial velocity (Vxi^ +Vyi^) m/s if the range of the projectile is double the maximum height, then Vy/Vx is(1) 1(2) 2(3) 3(4) 4

Profile image of Vikash Kumar Singh
8 Years agoGrade 12th pass
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1 Answer

Profile image of IHate Ppts
8 Years ago
We know that Vy/Vx=tan theta
 
Given that range=2maxheight
U2sin2theta/g=2U2sin2theta/2g
Simplifying, we get 2costheta=sin theta
Therefore, 2=sin theta/cos theta=tan theta
Therefore, answer is 2(2).