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A particle is thrown with a velocity u at an angle theta from the horizontal. Another particle is thrown with the same velocity at an angle a from the vertical. The ratio of times of flight of the two particles will be
A particle is thrown with a velocity u at an angle theta from the horizontal. Another particle is thrown with the same velocity at an angle a from the vertical. The ratio of times of flight of the two particles will be


2 years ago

Eshan
2095 Points
							Dear studnet,The time of flight of a projectile thrown at an anglefrom horizontal is given asFor projectile thrown forming same angle with vertical, the angle that it foms with horizontal is$90^{\circ}-\theta$Hence the time of flight is$t'=\dfrac{2usin(90^{\circ}-\theta)}{g}=\dfrac{2ucos\theta}{g}$Hence$\dfrac{t}{t'}=tan\theta$

2 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions