A particle is thrown vertically upwards from the ground. If the ratio of time of ascent to time of descent is √2/√3, then retardation produced due to resistive force acting on the particle is (a) 4 m/s^2 (b) 2 m/s^2 (c) 3 m/s^2 (d) 6 m/s^2

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Khimraj · Answer

t a /t d = ( t a /t d ) 2 = 2/3 = (10-a)/(10+a) 20 + 2a = 30 – 3a 5a = 10 so a = 2 m/s 2 Hope it clears........................................................................

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A particle is thrown vertically upwards from the ground. If the ratio of time of ascent to time of descent is √2/√3, then retardation produced due to resistive force acting on the particle is (a) 4 m/s^2 (b) 2 m/s^2 (c) 3 m/s^2 (d) 6 m/s^2

A particle is thrown vertically upwards from the ground. If the ratio of time of ascent to time of descent is √2/√3, then retardation produced due to resistive force acting on the particle is
(a) 4 m/s^2
(b) 2 m/s^2
(c) 3 m/s^2
(d) 6 m/s^2

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A particle is thrown vertically upwards from the ground. If the ratio of time of ascent to time of descent is √2/√3, then retardation produced due to resistive force acting on the particle is (a) 4 m/s^2 (b) 2 m/s^2 (c) 3 m/s^2 (d) 6 m/s^2

A particle is thrown vertically upwards from the ground. If the ratio of time of ascent to time of descent is √2/√3, then retardation produced due to resistive force acting on the particle is (a) 4 m/s^2 (b) 2 m/s^2 (c) 3 m/s^2 (d) 6 m/s^2

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A particle is thrown vertically upwards from the ground. If the ratio of time of ascent to time of descent is √2/√3, then retardation produced due to resistive force acting on the particle is
(a) 4 m/s^2
(b) 2 m/s^2
(c) 3 m/s^2
(d) 6 m/s^2