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A particle is thrown vertically upwards from the ground. If the ratio of time of ascent to time of descent is √2/√3, then retardation produced due to resistive force acting on the particle is (a) 4 m/s^2 (b) 2 m/s^2 (c) 3 m/s^2 (d) 6 m/s^2
A particle is thrown vertically upwards from the ground. If the ratio of time of ascent to time of descent is √2/√3, then retardation produced due to resistive force acting on the particle is (a) 4 m/s^2 (b) 2 m/s^2 (c) 3 m/s^2 (d) 6 m/s^2


2 years ago

Khimraj
3007 Points
							ta/td = $\sqrt{(g-a)/(g+a)}$(ta/td )2 = $(g-a)/(g+a)$2/3 = (10-a)/(10+a)20 + 2a = 30 – 3a5a = 10so a = 2 m/s2Hope it clears........................................................................

2 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions