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A particle is thrown vertically upwards from the ground. If the ratio of time of ascent to time of descent is √2/√3, then retardation produced due to resistive force acting on the particle is (a) 4 m/s^2 (b) 2 m/s^2 (c) 3 m/s^2 (d) 6 m/s^2

Harshit Raj , 6 Years ago
Grade 11
anser 1 Answers
Khimraj

Last Activity: 6 Years ago

ta/td = \sqrt{(g-a)/(g+a)}
(ta/td )2 = (g-a)/(g+a)
2/3 = (10-a)/(10+a)
20 + 2a = 30 – 3a
5a = 10
so a = 2 m/s2
Hope it clears........................................................................

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