A particle is thrown vertically upwards from the ground. If the ratio of time of ascent to time of descent is √2/√3, then retardation produced due to resistive force acting on the particle is (a) 4 m/s^2 (b) 2 m/s^2 (c) 3 m/s^2 (d) 6 m/s^2
Harshit Raj , 6 Years ago
Grade 11
1 Answers
Khimraj
Last Activity: 6 Years ago
ta/td =
(ta/td)2 =
2/3 = (10-a)/(10+a)
20 + 2a = 30 – 3a
5a = 10
so a = 2 m/s2
Hope it clears........................................................................
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