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Grade: 9

                        

A particle is thrown up with the velocity of 40m/s. The maximum height reached by the particle is?

3 years ago

Answers : (2)

salmankhan
20 Points
							
formula of maximum range is 
Rmax =U/g
substituting the value 
=40*40/10
=1600/10
=160 m
 
…...............................................................................................................
3 years ago
Janhavi
19 Points
							U^2sin^2theata/2g=height attainedTheata=90 i.e=1  and g=10(40)^2×1/2×10= max height attained  1600/20=80So max height attained by particle is 80 m.
						
3 years ago
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