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A particle is thrown up with the velocity of 40m/s. The maximum height reached by the particle is?

```
3 years ago

salmankhan
20 Points
```							formula of maximum range is Rmax =U2 /gsubstituting the value =40*40/10=1600/10=160 m …...............................................................................................................
```
3 years ago
Janhavi
19 Points
```							U^2sin^2theata/2g=height attainedTheata=90 i.e=1  and g=10(40)^2×1/2×10= max height attained  1600/20=80So max height attained by particle is 80 m.
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions