# A particle is released from a height H= 400m. Due to the wind the particle gathers the horizontal velocity component vx = (sqrt5)y, where y is the vertical displacement of the particle from the point of release, then find:(a) The horizontal drift of the particle when it strikes the ground.(b) the speed with which the particle strikes the ground.

Sumit Majumdar IIT Delhi
7 years ago
Dear student,
a) The horizontal velocity when it strikes the ground would be equal to
b) The vertical velocity would be given by:

Hence, the net velocity would be given by:

Regards
Sumit