Mohammed Kasib Siddiqui
Last Activity: 6 Years ago
Let the highest point be P and point of projection be O. The the time of flight is given by T=2usinB÷g
. Let the point Q be on the plane of projection such that it comes straight umder the pt. P .Join OPQ to form a triangle . Now PQ is the maximum height and OQ is half of range . Apply pythagoras theorem to find OP ie hypotenuse which will be our displacement.
Now avg. velocity=displacement÷time
Ie avg. velocity = OP÷ (usinB÷g)
As it is half of the range hence the time of flight is
T=usinB÷g