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Grade: 11
        
A particle is projected with a velocity u at an angle alpha with the horizontal. At what time its vertical component of velocity is half of its net speed at heighest point
 
one year ago

Answers : (1)

Khimraj
3008 Points
							
net speed at highest  point = ucos\alpha
then
v = u -gt
ucos\alpha/2 = usin\alpha – gt
Then
t = usin\alpha/g – ucos\alpha/2g
Hope it clears.
one year ago
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