Grade 11Mechanics

A particle is projected with a velocity 10 m/s at an angle 30 with horizontal . Find its distance from the point of projection 1/2 seconds later

Aayush

6 Years agoGrade 11

1 Answer

Vikas TU

6 Years ago

Dear student

T = 2uSinQ /g
T = 2*10 *1/20 = 1 sec
Displacement in 1/2 second
X = uCosQ
=> 10* sqrt 3 / 2 *1/2 = 4.33 meter
Distance in y in t = 1/2 second
Y = usin30 = 5 meter
Distance = sqrt (4.33^2 + 25) = 6.614 m
Regards

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A particle is projected with a velocity 10 m/s at an angle 30 with horizontal . Find its distance from the point of projection 1/2 seconds later

Aayush

1 Answer

Vikas TU

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